Q7 of 56 Page 14

If x=1 and y=6 is a solution of the equation 8x-ay+a2=0, find the values of a.

Given, x=1 and y=6 is a solution of the equation 8x-ay+a2=0


⇒ 8 × 1 – a × 6 + a2 = 0


⇒ a2 – 6a + 8 = 0


⇒ a2 – 4a – 2a + 8 = 0


⇒ a(a – 4) – 2(a – 4) = 0


⇒ (a – 2)(a – 4) = 0


⇒ a = 2, 4


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