Q10 of 56 Page 13

Find the value of k for which the point (1,-2) lies on the graph of the linear equation x-2y+k=0.

Given, (1,-2) lies on the graph of the linear equation x-2y+k=0


Thus, (1, -2) satisfies the equation


⇒ 1 + 4 + k = 0


⇒ k = - 5


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