The base of an isosceles triangle measures 80cm and its area is 360cm2 . Find the perimeter of the triangle.
Let us assume
be an isosceles triangle and let AL perpendicular BC

It is given that,
BC = 80 cm
Area of triangle ABC = 360 cm2
We know that,
Area of triangle = ![]()
= 360 cm2
= 360 cm2
= 360 cm2
= ![]()
= 9 cm
Now,
BL = ![]()
= (![]()
= 40 cm
a = ![]()
= ![]()
= ![]()
= ![]()
= 41 cm
Therefore,
Perimeter of the triangle = (41 + 41 + 80) = 162 cm
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