Two motor mechanics, Raju and Siraj, working together can overhaul a scooter in 6 hours. Raju alone can do the job in 15 hours. In how many hours can Siraj alone do it?
Number of hours Raju required to overhaul a scooter : 15 hours
Let number of hours siraj required to overhaul a scooter : X hours
Number of hours required by Raju and Siraj together to do a piece of work : 6 hours
Work done by Raju in one hour: ![]()
Work done by Siraj in one hour: ![]()
Work done by Raju and Siraj together in a one hour : ![]()
Work done by Raju and Siraj together in one hour :
=
= ![]()
![]()
⇒ 6X +90 = 15X
⇒ 9X = 90
⇒ X =
= 10 hours
Siraj can do the work 10 hours.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.