Q8 of 55 Page 67

Find the least number which when divided by 6, 15 and 18 leave remainder 5 in each case.

To find the required number we have to calculate LCM of 6, 15 and 18;



LCM = 2 × 3 × 3 × 5 = 90


Required number = 90+5 = 95


More from this chapter

All 55 →
6

The traffic lights at three different road crossings change after every 48 seconds, 72 seconds and 108 seconds respectively. If they change simultaneously at 7 a.m., at what time will they change simultaneously again?

 7

Three tankers contain 403 litres, 434 litres and 465 litres of diesel respectively. Find the maximum capacity of a container that can measure the diesel of the three containers exact number of times.

 9

Find the smallest 4-digit number which is divisible by 18, 24 and 32.

 10

Find the LCM of the following numbers:

(a) 9 and 4 (b) 12 and 5


(c) 6 and 5 (d) 15 and 4


Observe a common property in the obtained LCMs. Is LCM the product of two numbers in each case?