Q9 of 55 Page 67

Find the smallest 4-digit number which is divisible by 18, 24 and 32.

LCM 0f 18, 24 and 32



LCM = 2 × 2 × 2 × 2 × 2 × 3 × 3 = 288


We have to find the smallest 4-digit multiple of 288


It can be observed that


288 × 3 = 864 and


288 × 4 = 1152


Therefore, the smallest 4-digit number which is divisible by 18, 24 and 32 is 1152.


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Find the least number which when divided by 6, 15 and 18 leave remainder 5 in each case.

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Find the LCM of the following numbers:

(a) 9 and 4 (b) 12 and 5


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Find the LCM of the following numbers in which one number is the factor of the other:

(a) 5, 20 (b) 6, 18


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What do you observe in the results obtained?