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Q4 of 41 Page 240

Complete the table and by inspection of the table, find the solution to the equation 5t = 35.





































t



3



4



5



6



7



8



9



10



11



-



-



-



-



-



5t



-



-



-



-



-



-



-



-



-



-



-



-



-



-


For 5t, the table can be formed as follows:












































T



5t



3



5 × 3 = 15



4



5 × 4 = 20



5



5 × 5 = 25



6



5 × 6 = 30



7



5 × 7 = 35



8



5 × 8 = 40



9



5 × 9 = 45



10



5 × 10 = 50



11



5 × 11 = 55



From the above solution, we find that:


t = 7 is the solution of the given equation as


5t = 5 × 7


= 35


More from this chapter

All 41 →
3

Pick out the solution from the values given in the brackets next to each equation. Show that the other values do not satisfy the equation.

(a) 5m = 60 (10, 5, 12, 15)


(b) n + 12 = 20 (12, 8, 20, 0)


(c) p – 5 = 5 (0, 10, 5, -5)


(d) =7 (7, 2, 10, 14)


(e) r - 4 = 0 (4, -4, 8, 0)


(f) x + 4 = 2 (-2, 0, 2, 4)

4

Complete the table and by inspection of the table find the solution to the equation m + 10 = 16.



































M



1



2



3



4



5



6



7



8



9



10



--



--



--



m+10



-



-



-



-



-



-



-



-



-



-



-



-



-


4

Complete the table and find the solution of the equation = 4 using the table



































Z



8



9



10



11



12



13



14



15



16



-



-



-



-







3





-



-



-



-



-



-



-



-



-



-


4

Complete the table and find the solution to the equation m - 7 = 3.


































m



5



6



7



8



9



10



11



12



13



--



--



m -7



-



-



-



-



-



-



-



-



-



-



-


Questions · 41
11. Algebra
1 2 3 4 5 6 7 8 9 10 11 11 1 2 3 4 5 1 2 3 4 5 6 6 1 1 1 1 1 2 3 3 3 1 2 3 4 4 4 4 5
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