Find:
(i) 1/4 of (a) 1/4 (b) 3/5 (c) 4/5
(ii) 1/7 of (a) 2/9 (b) 6/5 (c) 3/10
(i) We have,
(a)
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=
× ![]()
= ![]()
(b)
of ![]()
=
× ![]()
= ![]()
(c) Also,
of ![]()
=
× ![]()
= ![]()
(ii) We have,
(a)
of ![]()
=
× ![]()
= ![]()
(b)
of ![]()
=
× ![]()
= ![]()
(c) Also,
of ![]()
=
× ![]()
= ![]()
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