Find:
(i)
(ii)
(iii) ![]()
(iv)
(v)
(vi) ![]()
(i) We have,
2
=
× ![]()
= ![]()
(ii) We have,
5
=
× ![]()
= ![]()
(iii) We have,
7
=
× ![]()
= ![]()
(iv) We have,
4
3
=
3
=
× ![]()
= ![]()
(v) We have,
3
4
=
4
=
× ![]()
= ![]()
(vi) We have,
4
7
=
7
=
× ![]()
= ![]()
Couldn't generate an explanation.
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