If 3cotθ = 2, show that 
We have 3cotθ = 2
→ cotθ = 2/3 (1)
Consider the LHS = ![]()
(Dividing the numerator and denominator by sinθ )
= 
= ![]()
=
(from(1))
= ![]()
= 2/6
= 1/3
= RHS
HENCE PROVED
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