If x = cosecA + cosA and y = cosecA - cosA the prove that 
x + y = cosecA + cosA + cosecA - cosA
= 2cosecA
→ sinA = 2/(x + y) = BC/AC
x - y = cosecA + cosA - (cosecA - cosA)
= cosecA + cosA - cosecA + cosA
= 2cosA
Consider the LHS,
= ![]()
= sin2A + cos2A - 1
= 1 - 1 (∵sin2A + cos2A = 1)
= 0
= RHS
HENCE PROVED
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