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Summative Assessment II
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Q15 of 78 Page 944

Solve for x: 12abx2 – (9a2 – 8b2) x – 6ab = 0.

12abx2 – (9a2 – 8b2)x – 6ab = 0


12abx2 – 9a2x + 8b2x– 6ab = 0


3ax(4bx – 3a) + 2b(4bx – 3a) = 0


(3ax + 2b)(4bx – 3a) = 0


So, we have


3ax + 2b = 0 or 4bx – 3a = 0



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Questions · 78
Summative Assessment II
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