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3. Electrochemistry
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Q8 of 33 Page 91

The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 S cm–1. Calculate its molar conductivity.

Given -


Molarity, C = 0.20 M


Electrolytic conductivity of a solution, κ = 0.0248 S cm–1


Molar conductivity = ?


Molar conductivity, ∧m = S cm2 mol-1



∴ ∧m = 124 S cm2 mol-1


Molar conductivity(∧m) of 0.20 M solution of KCl at 298 K is 124 S cm2 mol-1


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Define conductivity and molar conductivity of the solution of an electrolyte. Discuss their variation with concentration.

9

The resistance of a conductivity cell containing 0.001M KCl solution at 298 K is 1500 Ω. What is the cell constant if the conductivity of 0.001M KCl solution at 298 K is 0.146 × 10–3 S cm–1.

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The conductivity of sodium chloride at 298 K has been determined at different concentrations and the results are given below:



















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102 × κ/S m–1



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Questions · 33
3. Electrochemistry
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