Skip to content
Philoid
Browse Saved
Back to chapter
Chemistry
4. Chemical Kinetics
Home · Class 12 · Chemistry · Chemistry Part-I · 4. Chemical Kinetics
Prev
Next
Q28 of 39 Page 117

The decomposition of A into product has value of k as 4.5 × 103 s–1 at 10°C and energy of activation 60 kJ mol–1. At what temperature would k be 1.5 × 104s–1?

From Arrhenius equation, we obtain



Also, k1 = 4.5 × 103 s - 1


T1 = 273 + 10 = 283 K


k2 = 1.5 × 104 s - 1


Ea = 60 kJ mol - 1 = 6.0 × 104 J mol - 1


Then,



→ 0.5229 = 3133.627 × (T2-283)/(283 × T2)


→ 0.0472T2 = T2-283


T2 = 297K or T2 = 240 C


More from this chapter

All 39 →
26

The decomposition of hydrocarbon follows the equation

k = (4.5 × 1011s–1) e-28000K/T. Calculate Ea.

27

The rate constant for the first order decomposition of H2O2 is given by the following equation: log k = 14.34 – 1.25 × 104K/T

Calculate Ea for this reaction and at what temperature will its half-period be 256 minutes?

29

The time required for 10% completion of a first order reaction at 298K is equal to that required for its 25% completion at 308K. If the value of A is 4 × 1010s–1. Calculate k at 318K and Ea.

30

The rate of a reaction quadruples when the temperature changes from 293 K to 313 K. Calculate the energy of activation of the reaction assuming that it does not change with temperature.

Questions · 39
4. Chemical Kinetics
1 2 3 4 5 6 7 8 9 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
Back to chapter
ADVERTISEMENT
About Contact Privacy Terms
Philoid · 2026
  • Home
  • Search
  • Browse
  • Quiz
  • Saved