If the equation x2 + 5kx + 16 = 0 has no real roots then

Given the equation x2 + 5kx + 16 = 0 has no reala = 1 b = 5k c = 16Thus D = b2 - 4ac < 0= (5k)2 - 4.1.16 < 0= 25k2 - 64 < 025k2 = 64

Q25 of 293 Page 503

If the equation x² + 5kx + 16 = 0 has no real roots then

Given the equation x² + 5kx + 16 = 0 has no real

a = 1 b = 5k c = 16

Thus D = b² - 4ac < 0

= (5k)² - 4.1.16 < 0

= 25k² - 64 < 0

25k² = 64

The roots of the equation 2x² - 6x + 3 = 0 are

If the roots of 5x² - kx + 1 = 0 are real and distinct then

If the equation x² - kx + 1 = 0 has no real roots then

For what values of k, the equation kx² - 6x - 2 = 0 has real roots?