Write cubes of 5 natural numbers which are of the form 3n + 2 (e.g. 5, 8, 11, …) and verify the following: 'The cube of a natural number of the form 3n + 2 is a natural number of the same form'.

The 5 natural numbers which are of the form 3n + 2 (e.g 5, 8, 11 , …) are as follows:
3 ൱ + 2 = 3 + 2 = 5
3 ൲ + 2 = 6 + 2 = 8
3 ൳ + 2 = 9 + 2 = 11
3 × 4 + 2 = 12 + 2= 14
3 ൵ + 2 = 15 + 2 = 17
The cubes of 5 natural numbers which are of the form 3n + 2 (e.g 5, 8, 11, …) are as follows:
(5)³ = 5 ൵ × 5 = 125
(8)³ = 8 × 8 × 8 = 512
(11)³ = 11 × 11 × 11 = 1331
(14)³ = 14 × 14 × 14 = 2744
(17)³ = 17 × 17 × 17 = 4913
Verification:
125 = 3 × 41 + 2
512 = 3 × 170 + 2
1331 = 3 × 443 + 2
2744 = 3 × 914 + 2
4913 = 3 × 1637 + 2
.^.. 'The cube of a natural number of the form 3n + 2 is a natural number of the same form'.