What is the smallest number by which 8640 must be divided so that the quotient is a perfect cube ?
8640 = 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3 × 3 × 5
5 occurs as a prime number only once.
Hence, 5 is the smallest number by which 8640 must be
divided so that the quotient is a perfect cube.
5 occurs as a prime number only once.
Hence, 5 is the smallest number by which 8640 must be
divided so that the quotient is a perfect cube.
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