In the figure, ∠B = ∠C and AB = AC. Prove that BD = CE.
In ΔABD and ΔACE,
AB = AC ...... (given)
∠B = ∠C ...... (given)
∠A = ∠A ...... (common)
... ΔABD ≅ ΔACE ...... (By ASA criterion)
... BD = CE ...... (c.p.c.t.)
AB = AC ...... (given)
∠B = ∠C ...... (given)
∠A = ∠A ...... (common)
... ΔABD ≅ ΔACE ...... (By ASA criterion)
... BD = CE ...... (c.p.c.t.)
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