Q14 of 47 Page 7

In Δ ABC, B=35 o, C=65 o and the bisector of ABC meets BC in P. Arrange AP, BP and CP in descending order.

Given: B = 35 o


C = 65 o


The bisector of ABC meets BC in P


We have to arrange AP, BO and CP in descending order


In Δ ACP, we have


ACP > CAP


AP > CP (i)


In Δ ABP, we have


BAP > ABP


BP > AP (ii)


From (i) and (ii), we have


BP > AP > CP


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