Q5 of 33 Page 12

(i) The cross section of a canal is in a trapezium shape. If the canal is 10 m wide at the top, 6 m wide at the bottom and area of cross section is 72 sq. m, find the depth of the canal.
(ii) Find the area of a trapezium whose parallel sides are 12 cm and 16 cm and the distance between the parallel sides in 10 cm.

(i) Area of a trapezium = (sum of parallel sides) × height
                          or 72 = (6 + 10) ´ h
                                               Þ h = 9 m
(ii) Area of trapezium = (a + b)×h
                            = (12 + 16)휐
                            = 140 cm2 

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3 The perimeter of a triangular field is 240 m. It's two sides are 78 m and 50 m. Find the length of the altitude on the side of 50 m length from its opposite vertex. 4 (i) The area of an equilateral triangle is 100m2. Find the perimeter of the triangle.
(ii)  Find the base of an isosceles triangle whose area is 60 sq.cm and length of equal sides is 13 cm.
(iii) The area of an isosceles right triangle is 200 m2. Find its hypotenuse.
(iv) The ratio of the base to the altitude of a triangular field is 3 : 1. If the cost of cultivating the field at Rs 24.60 per hectare is Rs 332.10. Find its base and height. 6 The area of a quadrilateral is 360 m2 and the perpendiculars drawn to one of the diagonal from the opposite vertices are 10 m and 8 m. Find the length of the diagonal. 7 The area of a trapezium is 1700 m2. If one of the parallel sides is 64 m and the distance between the parallel sides is 34 m, find the length of the other parallel side.