A field is in the shape of a trapezium whose parallel sides are 25 m and 10 m. The non - parallel sides are 14 m and 13 m. Find the area of the field.
Given: Parallel sides of trapezium = 25 m and 10 m
Non – parallel sides of trapezium = =14 m and 13 m
To Find: Area of the field
Concept Used:
If sides of a triangle are a, b, and c, then area of a triangle is given by:
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Where s = semiperimeter of the triangle
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Diagram:

Construction:
From C, draw CE || DA.
Explanation:
Now, we can see that ADCE is a parallelogram in which AE || CD and AD || CE.
Now, we can get,
AE = 10 m and CE = 13 m
BE = AB – AE [From the figure]
Therefore,
BE = 25 m – 10 m = 15 m
Now Area of trapezium = Area of Parallelogram AECD + Area of triangle ECB
Let us first calculate the area of a triangle,
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s = 21 m
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Area = 3 × 7 × 4 m2
Area of Δ ECB = 84 m2
We also know that Area of Δ ECB = 1/2 (BE × CL)
84 = 1/2 (15 × CL)
15 × CL = 168
CL ![]()
CL = Height of the parallelogram
Now, Area of parallelogram ADCE = Base × Height
Area of parallelogram
= 112 m2
Hence, Area of Trapezium ABCD = (84 + 112) m2 = 196 m2.
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