A sphere of diameter 5 cm is dropped into a cylinder vessel partly filled with water. The diameter of the base of the vessel is 10 cm. If the sphere is completely submerged, by how much will the level of water rise?
Diameter of the sphere is 5 cm.
Radius of the sphere is 2.5 cm.
Diameter of the base of the vessel is 10 cm.
Radius of the base of the vessel is 5 cm.
Volume of the sphere =
π r3 =
×
× 2.5 × 2.5 × 2.5
Increase in the volume of water = Volume of the sphere
× 5 × 5 × h =
×
× 2.5 × 2.5 × 2.5
h =
=
Therefore the rise in the level of water is
cm.
Radius of the sphere is 2.5 cm.
Diameter of the base of the vessel is 10 cm.
Radius of the base of the vessel is 5 cm.
Volume of the sphere =
Increase in the volume of water = Volume of the sphere
h =
Therefore the rise in the level of water is
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