Q19 of 26 Page 294

A ‘thermacole’ icebox is a cheap and efficient method for storing small quantities of cooked food in summer in particular. A cubical icebox of side 30 cm has a thickness of 5.0 cm. If 4.0 kg of ice is put in the box, estimate the amount of ice remaining after 6 h. The outside temperature is 45 °C, and co-efficient of thermal conductivity of thermacole is 0.01 J s–1 m–1 K–1. [Heat of fusion of water = 335 × 103 J kg–1]

Given,

Side of the given cubical ice box, s = 30 cm = 0.3 m


Thickness of the ice box, l = 5.0 cm = 0.05 m


Mass of ice kept in the ice box, m = 4 kg


Time gap, t = 6 h = 6 × 60 × 60 s = 21600 s


Outside temperature, T = 45°C


Coefficient of thermal conductivity of thermacole,


K = 0.01 J s–1 m–1 K–1


Heat of fusion of water, L = 335 × 103 J kg–1


Let m’ be the total amount of ice that melts in 6 h.


The amount of heat lost by the food, θ = KA(T - 0)t/l


Where, A = Surface area of the box = 6×s×2 = 6×0.3×2 = 0.54 m3


θ = [(0.01 Js–1m–1K–1)×(0.54m3)×(45°C)×(21600s)]/(0.05 m)


θ = 104976 J


But θ = m'L


m’ = θ/L = 104976/(335 × 103 J kg-1)


m’ = 0.313 g


Mass of ice left = 4 0.313 = 3.687 kg


Hence, the amount of ice remaining after 6 h is 3.687 kg.


NOTE: Heat of fusion is the amount of heat supplied to a specific quantity of the substance to change its state from a solid to a liquid at constant pressure.


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(a) CO2 at 1 atm pressure and temperature – 60 °C is compressed isothermally.


Does it go through a liquid phase?


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18

A child running a temperature of 101°F is given an antipyrin (i.e. a medicine that lowers fever) which causes an increase in the rate of evaporation of sweat from his body. If the fever is brought down to 98 °F in 20 min, what is the average rate of extra evaporation caused, by the drug. Assume the evaporation mechanism to be the only way by which heat is lost. The mass of the child is 30 kg. The specific heat of human body is approximately the same as that of water, and latent heat of evaporation of water at that temperature is about 580 cal g–1.

20

A brass boiler has a base area of 0.15 m2 and thickness 1.0 cm. It boils water at the rate of 6.0 kg/min when placed on a gas stove. Estimate the temperature of the part of the flame in contact with the boiler. Thermal conductivity of brass = 109 J s–1 m–1 K–1; Heat of vaporisation of water = 2256 × 103 J kg–1.

21

Explain why:

a body with large reflectivity is a poor emitter