Q7 of 25 Page 8

Using binomial theorem, evaluate each of the following (102)5


(102)5 = (100 + 2)5

          = 5C0(100)5 + 5C1(100)4(2) + 5C2(100)3(2)2 + 5C3(100)2(2)3 + 5C4(100)(2)4 + 5C5(2)5

          =10000000000 + 5(100000000)(2)+10(1000000)(4)+ 10(10000)(8) + 5(100)(16) + 32

          = 10000000000+1000000000 + 40000000 + 800000 + 8000 + 32

          = 11040808032

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