Q16 of 25 Page 8

Prove that a b7 in (a-2b)12


Let a5b7 occurs in the (r + 1)th term, in the expansion of (a - 2b)12 given by I2Cr. a12 – r(-2b)r. Then 12 – r = 5. This gives r= 7. 
Thus the coefficient of a5b7 is

12C5 (-2)7 = (-128) = (792) (-128) = -101376

More from this chapter

All 25 →