Find the position and size of the virtual image formed when an object 2 cm tall is placed 20 cm from:

(i) a diverging lens of focal length 40 cm.

(ii) A converging lens of focal length 40 cm.

An object is placed 20 cm from

(a) A converging lens, and

(b) A diverging lens, of focal length 15 cm. Calculate the image position and magnification in each case.

A 2.0 cm tall object is placed 40 cm from a diverging lens of focal length 15 cm. Find the position and size of the image.

A small object is placed 150 mm away from a diverging lens of focal length 100 mm.

(i) Copy the figure below and draw rays to show how an image is formed by the lens.

(ii) Calculate the distance of the image from the lens by using the lens formula.

The diverging lens in part (a) is replaced by a converging lens also of focal length 100 mm. The object remains in the same position and an image is formed by the converging lens. Compare two properties of this image with those of the image formed by the diverging lens in part (a).