Q1 of 40 Page 25

Show that is 4√2 an irrational number.

Let us assume that 4√2 is a rational number



where, b≠0 and a, b are integers



∵ a, b are integers ∴ 4b is also integer


is rational which cannot be possible


∵ which is an irrational number


∵ it is contradicting our assumption


∴ the assumption was wrong


Hence, 4√2 is an irrational number


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