Multiply
i. √3(√7 – √3)
ii. (√5 – √7)√2
iii. (3√2 – √3)(4√3 – √2)
i. √3(√7 – √3)
=√3 × √7 – √3 × √3
[∵√a(√b–√c)=√a×√b–√a×√c]
=√21 – 3 [∵√a×√b=√ab and √a×√a=a]
⇒ √3(√7 – √3) = –3 + √21
ii. (√5 – √7)√2
=√5 × √2 – √7 × √2
[∵√a(√b–√c)=√a×√b–√a×√c]
=√10 – √14 [∵√a×√b=√ab]
⇒ (√5 – √7)√2 =√10 – √14
iii. (3√2 – √3)(4√3 – √2)
=3√2(4√3 – √2) – √3(4√3 – √2)
=3√2×4√3 – 3√2×√2 – √3×4√3 + √3×√2
[∵√a(√b–√c)=√a×√b–√a×√c]
=12√6 – 3×2 – 4×3 + √6 [∵√a×√b=√ab]
=12√6 – 6 – 12 + √6
=13√6 – 18
⇒ (3√2 – √3)(4√3 – √2) = 13√6 – 18
Couldn't generate an explanation.
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