Q2 of 35 Page 62

In a parallelogram ABCD, If ∠A = (3x +12)°, ∠B = (2x -32) ° then find the value of x and then find the measures of ∠C and ∠D.


∠A = (3x +12)°


∠B = (2x -32) °


∠A + ∠B = 180° (supplementary angles of the ∥gram)


(3x +12) + (2x -32) = 180


5x – 20 = 180°


∴ x= 32°


∠A = 3 × 32 +12 = 108° ⇒ ∠C = 108° (opposite ∠s are congruent)


Similarly, ∠B = 2× 32 – 32 = 32° ⇒ ∠D is 32°


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