Q4 of 35 Page 69

Diagonals of a rhombus are 20 cm and 21 cm respectively, then find the side of rhombus and its perimeter.

Let the diagonal AC = 20cm and BD = 21

AB2 = BO2 + AO2


AB2 = (10.5)2 + (10)2


(the diagonals of a rhombus bisect each other at 90°)


AB2 = 110.25 + 100


AB = √210.25 = 14.5cm (side of the rhombus)


Perimeter = 4a = 14. 5 × 4 = 58cm


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