Total surface area of a cube is 5400 sq. cm. Find the surface area of all vertical faces of the cube.
Given: Total surface area of cube = 5400 cm2
And we know total surface area of cube is given by,
TSA = 6 (side)2
⇒ 5400 = 6 (side)2 [∵, it given that TSA = 5400 cm2]
⇒ (side)2 = 5400/6
⇒ (side)2 = 900
⇒ side = √900
⇒ side = 30
Now we know side = 30 cm.
Let side = s.
So, to find surface area of all vertical faces of the cube, we need to add front side area, back side area, left side area and right side area of the cube.
∴, Surface area (SA) = (Area of front face) + (Area of back face) + (Area of left face) + (Area of right face)
⇒ SA = s2 + s2 + s2 + s2 = 4s2
⇒ SA = 4 (30)2
⇒ SA = 3600
Thus, surface area of all vertical faces of the cube is 3600 cm2.
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