Q2 of 26 Page 26

The diagonals AC and BD of rectangle ABCD intersect in point O. If m∠CAB = 25° find m∠DAC and m∠ACD.


As we know that, In rectangle every angle is 90


Hence,


∠CAB+∠DAC = 90°


⇒ ∠DAC = 90° - ∠CAB


⇒ ∠DAC = 90°-25°


⇒ ∠DAC = 65°


As we know that, In rectangle opposite sides are parallel


∠CAB = ∠ACD [By alternate interior angles]


Hence;



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