The diagonals seg XZ and seg YW of the rhombus XYZW intersect at point P. If l(XP) = 8 cm, find l(XZ).

The diagonals of rhombus are perpendicular bisectors of each other
XP = PZ [by above statement]
XZ = XP+PZ [by diagram]
XZ = 2× XP
XZ = 2× 8cm = 16cm
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