Q5 of 11 Page 144

Solve the following problems.

How much time a satellite in an orbit at height 35780 km above earth’s surface would take, if the mass of the earth would have been four times its original mass?

Given G = gravitational constant = 6.67 x 10-11 N m2/kg2


M mass of earth = 4 x 6 x 1024 kg


R = 6400 km


h = height of satellite above earth’s surface = 35780 km


R+h = 6400 + 35780 = 42180 km = 42180 x 103 m


v = ?


we know


v = √


=


v = 6.16 km/s


We know v = distance/time


= circumference/time


= 2πr/T


T =


T =


T = 43001.68 sec


T = 11.94 hr or approximately 12 hours.


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