Q5 of 11 Page 144

Solve the following problems.

If the height of a satellite completing one revolution around the earth in T seconds is h1 meter, then what would be the height of a satellite taking 2√2 T seconds for one revolution?

From Kelper’s second law of motion:


T2 ∝ r3/2


Here, r1 = r when, T1 = t


Then, if T2 = 2√2t


Then,


R2= ?


∴


⇒


⇒


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