Solve the following problems:
Liquid ammonia is used in ice factory for making ice from water. If water at 20oC is to be converted into 2 kg ice at 0oC, how many grams of ammonia are to be evaporated?
(Given: The latent heat of vaporization of ammonia= 341 cal/g)
Given: Latent heat of vapourisation of Ammonia =341 cal/g
The amount of heat supplied to raise the temperature will be given as:
Q = mcΔT
⇒ Q = 2kg × 1C/°-g× 20° C
⇒ Q = 2000 g×1C/°-g × 20 cal/g
⇒ Q = 40,000 cal
Now, let “m” be the amount of ammonia to be evaporated to do. Then, heat gained by ice will be:
Q = m’L
⇒ ![]()
⇒ m’ = 117 g
∴ 117 grams of ammonia should be evaporated.
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