Solve the following problems:
A thermally insulated pot has 150 g ice at temperature 0oC. How much steam of 100oC has to be mixed to it, so that water of temperature 50oC will be obtained? (Given : latent heat of melting of ice = 80 cal/g, latent heat of vaporization of water = 540 cal/g, specific heat of water = 1 cal/g °C)
The figure of this question is given as:

Now, the heat required, Q = mice × Lfusion
⇒ Q = 150 g × 80 cal/g
⇒ Q = 12000 cal = 12 kcal
Now,
Q = 150g× (1 cal/g) (500 – 00C)
=150× 50 = 7500 cal = 7.5 kcal
Now, the net heat transfer, QT = 12kcal – 7.5 kcal
= 4.5 kcal
Now, QT = msteam × Lmelting
⇒ 4.5 kcal = m× 540 cal/g
⇒ ![]()
⇒ m = 8.33 g
∴ 8.33 g of steam is required.
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