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3. square-square root and cube-cube root
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Q95 of 142 Page 88

Write the Pythagorean triplet whose one of the numbers is 4.

Given:

We know that for any natural number greater than 1, (2m, m2-1, m2 + 1) is a the Pythagorean triplet.


So if one number is 2m then other two number are m2-1 and m2 + 1.


i.e. 2m = 4 (given)


⇒ m = 2


Then m2-1 = 22-1 = 4-1 = 3


And m2 + 1 = 22 + 1 = 4 + 1 = 5


Hence, Pythagorean triplet is 3, 4 and 5


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Questions · 142
3. square-square root and cube-cube root
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