Q130 of 142 Page 88

Find three numbers in the ratio 2 : 3 : 5, the sum of whose squares if 608.

Given:

Let the three numbers are 2x, 3x and 5x


Acc. To given condition:


i.e (2x)2 + (3x)2 + (5x)2 = 608


⇒ 4(x)2 + 9(x)2 + 25 (x)2 = 608


⇒38(x)2 = 608


⇒ (x)2 = 16


⇒ x = 4


Hence, numbers are 2(4) = 8


3(4) = 12


5(4) = 20


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