Classify the following numbers as rational or irrational.
i. ![]()
ii. ![]()
iii. ![]()
iv. ![]()
v. 2π
vi. ![]()
vii. ![]()
i. 5 - √3
Here, 5 is a rational number and √3 is an irrational number.
We know that subtraction of a rational number and an irrational number always gives an irrational number.
∴ 5 - √3 is an irrational number.
ii. √3 + √2
Here, both √3 and √2 are irrational numbers.
We know that sum of two irrational number is always an irrational number.
∴ √3 + √2 is an irrational number.
iii. (√2 – 2)2
We know that (√a - b)2 = a - 2√a(b) + b2.
Comparing with the given expression,
⇒ a = 2; b = 2
On simplification, we get
⇒ (√2 – 2)2 = 2 – 2 (√2) (2) + 22
= 2 – 4√2 + 4
= 6 – 4√2
Here, 6 is a rational number and 4√2 is an irrational number.
We know that subtraction of a rational number and an irrational number always gives an irrational number.
∴ 6 - 4√2 is an irrational number.
iv. ![]()
On simplification, we get
⇒ ![]()
which is a rational number.
v. 2π
Here, 2 is a rational number and π is an irrational number.
We know that the product of a rational number and an irrational number is always an irrational number.
∴ 2π is an irrational number.
vi. ![]()
Here, 1 is a rational number and √3 is an irrational number.
We know that division of a rational number and an irrational number gives an irrational number.
∴
is an irrational number.
vii. (2 + √2) (2 - √2)
We know that (a + √b) (a - √b) = a2 – b.
Comparing with the given expression,
⇒ a = 2; b = 2
∴ (2 + √2) (2 - √2) = 22 – (√2)2
= 4 – 2 = 2
Here, 2 is a rational number.
∴ (2 + √2) (2 - √2) is rational.
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is represented by p. But we say that π is an irrational number. Why?