Rationalise the denominators of the following:
i.
ii. 
iv.
i. ![]()
Here, the conjugate of the denominator (3 + √2) is (3 - √2).
By rationalizing,
⇒ ![]()
We know that (a + √b) (a - √b) = a2 – b.
![]()
∴ ![]()
ii. ![]()
Here, the conjugate of the denominator (√7 - √6) is (√7 + √6).
By rationalizing,
⇒ ![]()
We know that (√a + √b) (√a - √b) = a – b.
![]()
∴ ![]()
iii. ![]()
By rationalizing the denominator,
⇒ ![]()
∴ ![]()
iv.![]()
Here, the conjugate of the denominator (√3 - √2) is (√3 + √2).
By rationalizing,
⇒ ![]()
We know that (√a + √b) (√a - √b) = a – b.
![]()
![]()
![]()
![]()
∴ ![]()
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is represented by p. But we say that π is an irrational number. Why?
ii. 
iv. 