Fill in the blanks to make the statements true.
Find the value [4–1 +3–1 + 6–2]–1.
we know that,
a-m = ![]()
⇒ [4–1 +3–1 + 6–2]–1 = ![]()
⇒ [4–1 +3–1 + 6–2]–1 = ![]()
⇒ [4–1 +3–1 + 6–2]–1 =
{∵ L.C.M. of (4,3,36) is 36}
⇒ [4–1 +3–1 + 6–2]–1 =![]()
Hence, [4–1 +3–1 + 6–2]–1 =
.
Couldn't generate an explanation.
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