Find the value of x so that

(–2)³ × (–2)^–6 = (–2)^2x–1

from the laws of exponents , we know that,

a^m × aⁿ = a^(m+n)

So , we have , (–2)³ × (–2)^–6 =(-2)^(3)+(-6) = (-2)^(-3)

Now , we have , (-2)^(-3)= (-2)^(2x-1)

On comparing both the sides , we get ,

-3 = 2x-1

2x = -3 + 1

2x = -2

x = = -1

∴ x = -1