Q15 of 39 Page 141

The parking charges of a car in Hyderabad Railway station for first two hours is ₹ 50 and ₹10 for each subsequent hour. Write down an equation and draw the graph. Find the following charges from the graph

(i) For three hours


(ii) For six hours


(iii) How many hours did Rekha park her car if she paid ₹ 80 as parking charges?

Give that, the parking charges of a car for first two hours is Rs. 50 and Rs. 10 for each subsequent hour.

⇒ the extra charges for first two hours apart from Rs. 10 per hour = 50-(10× 2)


= 30


Now, let ‘x’ be no. of hours and ‘y’ be the parking charges.


⇒ y = 10x + 30 is the equation.


For graph, we’ll first make the table of solutions by putting some random values of x and thereafter we’ll find corresponding values of y and then we’ll plot these points on graph, join them and extend them in straight line to find the graph.


(Note: ∵ equation is linear graph will always be straight line.)


Table of solutions for the given equation-



GRAPH:



(Note: Negative values are taken just to make graph but these values are practically impossible)


(i)Given, x = 3 hr.


From the graph, the corresponding y = 60 hr. (pt. E)


(ii)Given, x = 6 hr.


From the graph, the corresponding y = 90 hr. (pt. F)


(iii)Given, y = Rs. 80


From the graph, the corresponding x = 5 hr. (pt. G)


(where, No. of hours = x ; Parking charges = y)


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Write the linear equation representing this information and draw the graph. With the help of graph find the distance travelled if the fare paid is ₹ 55? How much would have to be paid for 7 kilometers?

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A lending library has fixed charge for the first three days and an additional charges for each day thereafter. John paid ₹ 27 for a book kept for seven days. If the fixed charges be ₹ x and subsequent per day charges be ₹ y, then write the linear equation representing the above information and draw the graph of the same. From the graph if the fixed charge is ₹ 7 the subsequent per day charge ? and if the per day charge is ₹ 4/- find the ‘fixed’ charge ?

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Sameera was driving a car with uniform speed of 60 kmph. Draw distance-time graph. From the graph find the distance travelled by Sameera in

(i)


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The ratio of molecular weight of Hydrogen and Oxygen in water is 1:8. Set up an equation between Hydrogen and Oxygen and draw its graph. From the graph find the quantity of Hydrogen if Oxygen is 12 grams. And quantity of oxygen if hydrogen is gms.?

[Hint : If the quantities of hydrogen and oxygen or ‘x’ and ‘y’ respectively, then x : y = 1:8 ⟹ 8x = y]