The lengths of 40 leaves of a plant are measured correct to the nearest millimeter, and the data obtained is represented in the following table :

Find the median length of the leaves. (Hint : The data needs to be converted to continuous classes for finding the median, since the formula assumes continuous classes. The classes then change to 117.5 – 126.5, 126.5 – 135.5, ….., 171.5 – 180.5.)
We’ll convert this inclusive data into exclusive data type.

For median:
We have, total frequency, N = 40
N/2 = 40/2 = 20
Observe, cf = 29 is just greater than 20.
Thus, median class = 144.5-153.5
Median is given by

Where,
L = Lower class limit of median class = 144.5
N/2 = 20
cf = cumulative frequency of the class preceding median class = 17
f = frequency of the median class = 12
h = class interval of the median class = 9
Substituting these values in the formula of median, we get
![]()
⇒ ![]()
⇒ Median = 144.5 + 9/4
⇒ Median = 144.5 + 2.25
⇒ Median = 146.75
Thus, the median is 146.75 mm.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.



