Q4 of 25 Page 346

The lengths of 40 leaves of a plant are measured correct to the nearest millimeter, and the data obtained is represented in the following table :


Find the median length of the leaves. (Hint : The data needs to be converted to continuous classes for finding the median, since the formula assumes continuous classes. The classes then change to 117.5 – 126.5, 126.5 – 135.5, ….., 171.5 – 180.5.)

We’ll convert this inclusive data into exclusive data type.


For median:


We have, total frequency, N = 40


N/2 = 40/2 = 20


Observe, cf = 29 is just greater than 20.


Thus, median class = 144.5-153.5


Median is given by



Where,


L = Lower class limit of median class = 144.5


N/2 = 20


cf = cumulative frequency of the class preceding median class = 17


f = frequency of the median class = 12


h = class interval of the median class = 9


Substituting these values in the formula of median, we get




Median = 144.5 + 9/4


Median = 144.5 + 2.25


Median = 146.75


Thus, the median is 146.75 mm.


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