Q8 of 75 Page 216

In a hot water heating system, there is a cylindrical pipe of length 28 m and diameter5 cm. Find the total radiating surface in the system.

Height (h) of cylindrical pipe = Length of cylindrical pipe = 28 m

Radius (r) of circular end of pipe =


= 2.5 cm


= 0.025 m


CSA of cylindrical pipe = 2πrh


= 2 * * 0.025 * 28 m2


= 4.4 m2


The area of the radiating surface of the system is 4.4 m2


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