Q12 of 24 Page 31

A particle covers 10m in first 5s and 10m in next 3s. Assuming constant acceleration. Find initial speed, acceleration and distance covered in next 2s.

Let the initial speed be u m/s and speed after 5s be v1m/s.


Let acceleration of the particle be a m/s2.


v1 = u + 5a …(using v = u + at) …(1)


Now for first 5s, distance s1


(2)


For next 3s, v1 will be its initial velocity


and distance s2


...(3)


Now s1-s2 = 0








Putting value of u in equation (2), we get





…(5)


So (from equation (4))



Given, Distance in 8sec = 10m + 10m = 20m


Distance in 10sec




Distance covered in next 2sec




=


= 8.33 m


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