Q6 of 23 Page 117

What is the speed of an apple dropped from a tree after 1.5 seconds? What distance will it cover during this time? Take g = 10m/s2

Since Apple dropped from a tree.

Initial speed (u) = 0 m/s


Given in question;


Time (t) = 1.5 s


Acceleration due to gravity (g) = 10 m/s2


Now;


By Newton’s equation of motion


V = u + at.


Here a = g = 10 m/s2.


T = 1.5 s;


U = 0 m/s


Final speed (v) = u + gt.


v = 0 + 10 x 1.5.


v = 15 m/s


Hence the speed of an apple dropped from a tree after 1.5 second is 15 m/s


By Newton’s equation of motion


S = ut +


Here a = g = 10 m/s2.


T = 1.5 s;


U = 0 m/s


Distance (S) = ut +


s = 0 x 1.5 +


s = 0 +


s = .25 m.


Hence distance covered by an apple is 11.25 m.


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