What is the speed of an apple dropped from a tree after 1.5 seconds? What distance will it cover during this time? Take g = 10m/s2
Since Apple dropped from a tree.
∴ Initial speed (u) = 0 m/s
Given in question;
Time (t) = 1.5 s
Acceleration due to gravity (g) = 10 m/s2
Now;
By Newton’s equation of motion
V = u + at.
Here a = g = 10 m/s2.
T = 1.5 s;
U = 0 m/s
⇒ Final speed (v) = u + gt.
⇒ v = 0 + 10 x 1.5.
⇒ v = 15 m/s
Hence the speed of an apple dropped from a tree after 1.5 second is 15 m/s
By Newton’s equation of motion
S = ut + ![]()
Here a = g = 10 m/s2.
T = 1.5 s;
U = 0 m/s
Distance (S) = ut + ![]()
⇒ s = 0 x 1.5 + ![]()
⇒ s = 0 + ![]()
⇒ s =
.25 m.
Hence distance covered by an apple is 11.25 m.
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