A scooter weighing 150kg together with its rider moving at 36 km/hr is to take a turn of radius 30 m. What force on the scooter towards the center is needed to make the turn possible? Who or what provides this?
According to the question;
Radius of circular path (r) = 30 m;
Velocity of scooter (v) = 36 km/hr;
=
m/s;
= 10 m/s.
Mass of scooter (m) = 150 kg;
For making the turn possible the scooter needs force equal to the centripetal force which is given by;
F = ![]()
⇒ F = ![]()
⇒ F = 5 x 10 x 10 = 500 N.
The force required is 500 N and it is provided by the normal reaction between the ground and the scooter.
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