Q7 of 44 Page 89

The following table shows the age distribution of cases of certain disease reported during a year in a particular city.


Obtain the mean, median and mode of the above data.

We have


For Mean:


Mean is given by



[from the table]


Mean = 32.1


For Median:


Here, we get total frequency, fi = N = 50. So,



Since, N/2 = 25. Mark a cumulative frequency which is just greater than 25.


Here, it is 29. So, median class would be 24.5 – 34.5.


Median is given by



Where, l = lower limit of the median class = 24.5


N/2 = 25 (as calculated above)


m = cumulative frequency of the class preceding the median class = 17


f = frequency of the median class = 12


c = width of the median class = 10


Putting all these values in the formula, we get




Median = 24.5 + 6.67 = 31.167


For Mode:


We have the following data in exclusive type in tabular form. We can interpret the column ‘No. of cases’ as frequency.



Note that, highest frequency = 12


Corresponding class interval = 24.5 – 34.5


Modal class = 24.5 – 34.5


Mode is given by,



Where, l = lower limit of the modal class = 24.5


f = frequency of the modal class = 12


f1 = frequency of the class preceding the modal class = 11


f2 = frequency of the class succeeding the modal class = 10


c = width of the class interval = 10


Putting all these values in the modal formula,





Mode = 24.5 + 3.33


Mode = 27.83


Thus, mean is 32.1, median is 32.167 and mode is 27.83.


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