The following table shows the age distribution of cases of certain disease reported during a year in a particular city.

Obtain the mean, median and mode of the above data.
We have

For Mean:
Mean is given by
![]()
⇒
[from the table]
⇒ Mean = 32.1
For Median:
Here, we get total frequency, ∑fi = N = 50. So,
![]()
Since, N/2 = 25. Mark a cumulative frequency which is just greater than 25.
Here, it is 29. So, median class would be 24.5 – 34.5.
Median is given by

Where, l = lower limit of the median class = 24.5
N/2 = 25 (as calculated above)
m = cumulative frequency of the class preceding the median class = 17
f = frequency of the median class = 12
c = width of the median class = 10
Putting all these values in the formula, we get
![]()
⇒ ![]()
⇒ Median = 24.5 + 6.67 = 31.167
For Mode:
We have the following data in exclusive type in tabular form. We can interpret the column ‘No. of cases’ as frequency.

Note that, highest frequency = 12
Corresponding class interval = 24.5 – 34.5
⇒ Modal class = 24.5 – 34.5
Mode is given by,
![]()
Where, l = lower limit of the modal class = 24.5
f = frequency of the modal class = 12
f1 = frequency of the class preceding the modal class = 11
f2 = frequency of the class succeeding the modal class = 10
c = width of the class interval = 10
Putting all these values in the modal formula,
![]()
⇒ ![]()
⇒ ![]()
⇒ Mode = 24.5 + 3.33
⇒ Mode = 27.83
Thus, mean is 32.1, median is 32.167 and mode is 27.83.
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